2x^2-7x-1=3

Solution for 2x^2-7x-1=3 equation:

Simplifying
2x2 + -7x + -1 = 3

Reorder the terms:
-1 + -7x + 2x2 = 3

Solving
-1 + -7x + 2x2 = 3

Solving for variable 'x'.

Reorder the terms:
-1 + -3 + -7x + 2x2 = 3 + -3

Combine like terms: -1 + -3 = -4
-4 + -7x + 2x2 = 3 + -3

Combine like terms: 3 + -3 = 0
-4 + -7x + 2x2 = 0

Factor a trinomial.
(-1 + -2x)(4 + -1x) = 0

Subproblem 1
Set the factor '(-1 + -2x)' equal to zero and attempt to solve:

Simplifying
-1 + -2x = 0

Solving
-1 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2x = 0 + 1
-2x = 0 + 1

Combine like terms: 0 + 1 = 1
-2x = 1

Divide each side by '-2'.
x = -0.5

Simplifying
x = -0.5
Subproblem 2
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Solution
x = {-0.5, 4}